What mass of water, H_2OH2O, can be produced from 150 grams of ammonia, NH_3NH3?

1 Answer
Feb 20, 2016

238 g

Explanation:

NH_3+3/4O_2 =1/2N_2+3/2H_2ONH3+34O2=12N2+32H2O

As guided by the above equation, we see 1 mole "NH"_3NH3 produces 1.5 moles of water.

Hence "150 g NH"_3 =150/17 "mol NH"_3150 g NH3=15017mol NH3 produces 150/17*1.5150171.5 moles "H"_2"O"H2O which will have a mass 150/17*1.5 × "molar mass of H"_2"O"150171.5×molar mass of H2O

=150/17*1.5*18=238=150171.518=238