What mass of water, #H_2O#, can be produced from 150 grams of ammonia, #NH_3#? Chemistry Stoichiometry Stoichiometry 1 Answer P dilip_k · Ernest Z. Feb 20, 2016 238 g Explanation: #NH_3+3/4O_2 =1/2N_2+3/2H_2O# As guided by the above equation, we see 1 mole #"NH"_3# produces 1.5 moles of water. Hence #"150 g NH"_3 =150/17 "mol NH"_3# produces #150/17*1.5# moles #"H"_2"O"# which will have a mass #150/17*1.5 × "molar mass of H"_2"O"# #=150/17*1.5*18=238# Answer link Related questions How do you solve a stoichiometry problem? What is stoichiometry? Question #93ac6 Why do we study stoichiometry? How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 See all questions in Stoichiometry Impact of this question 2480 views around the world You can reuse this answer Creative Commons License