# What mass of water, H_2O, can be produced from 150 grams of ammonia, NH_3?

Feb 20, 2016

238 g

#### Explanation:

$N {H}_{3} + \frac{3}{4} {O}_{2} = \frac{1}{2} {N}_{2} + \frac{3}{2} {H}_{2} O$

As guided by the above equation, we see 1 mole ${\text{NH}}_{3}$ produces 1.5 moles of water.

Hence ${\text{150 g NH"_3 =150/17 "mol NH}}_{3}$ produces $\frac{150}{17} \cdot 1.5$ moles $\text{H"_2"O}$ which will have a mass 150/17*1.5 × "molar mass of H"_2"O"

$= \frac{150}{17} \cdot 1.5 \cdot 18 = 238$