What torque would have to be applied to a rod with a length of #8 m# and a mass of #8 kg# to change its horizontal spin by a frequency #15 Hz# over #4 s#?

1 Answer
Feb 8, 2016

Answer:

#L=-1408*pi#

Explanation:

#alpha :"angular acceleration"#
#L: "Torque"#
#I: "moment of inertia"#
#"Torque is given by formula": L=alpha *I#
#L=2*pi(omega_l-omega_i)/(Delta t)*I#
#L=2*pi(4-15)/4 *I#
#L=-11 *pi/4 *I#
#I=m*r^2#
#I=8*64=512#
#L=-11*pi/4 *512#
#L=-11*128*pi#
#L=-1408*pi#