Question

Which is the quadratic variation equation for the relationship given y varies directly with x^2 and y = 36 when x = 3?

Answer 1

`y=4x^2`

Explanation:

As `y` varies directly with `x^2`, we can write this as

`y=ax^2`

Now we have `y=36` when `x=3`, hence

`36=axx3^2` or `9a=36` or `a=36/9=4`

and hence relation is `y=4x^2`