Question

The height of a vertical cone is 24.5cm. If the angle at the apex is 48º37'10", how do you find the length of the slant edge of the cone?

Answer 1

The length of the slant edge od the cone is `26.88cm` to 2 decimal places

Explanation:

Assumption: The angel given is between the opposing sides and not between vertical and the side.

Know: `AD = ACcos(/_DAC)`

`/_DAC =(/_ABC)/2 =24^o18'35''`

`=> AC=(AD)/(cos(24^o18'35'')) =( 24.5)/(cos(24^o18'35'')`

`AC=26.88374cm`

`AC=26.88cm` to 2 decimal places

'~~~~~~~~~~~~~~~~~~ Foot Note ~~~~~~~~~~~~~~~

`35'' = 35/(60xx60)` degrees
`18' = 18/60` degrees

So `24^o18'35'' = 24+18/60+35/3600` degrees