How do you graph #r^2= 16cos2θ#? Trigonometry The Polar System Graphing Basic Polar Equations 1 Answer Sihan Tawsik Jan 28, 2016 here is how Explanation: graph{y^2=16cos2x [-10, 10, -5, 5]} Answer link Related questions What are limacons and cardioids? How do you graph basic polar equations? How do you determine the shape of a limaçon from the polar equation? How do you graph #r = 1.5#? How do you graph #\theta = 30^\circ#? What does the graph of #r = \cos \theta# such that #0^\circ \le \theta \le 360^\circ# look like? What is the general form of limacons and cardioids and how do you graph transformations? How do you graph the equation #r = 1 + cos( theta )#? How do you graph #r=3-2costheta#? How do you graph #r=1-cosx#? See all questions in Graphing Basic Polar Equations Impact of this question 4364 views around the world You can reuse this answer Creative Commons License