Question

How many grams of aluminum are required to produce 8.70 moles of aluminum chloride in the reaction `2Al + 3Cl_2 -> 2AlCl_3`?

Answer 1

`234.9g`

Explanation:

The balanced chemical equation represents the mole ratio in which the chemicals combine, and in this case illustrates that `2 mol Al` produces `2molAlCl_3`, hence these 2 chemicals are in a `1:1` ratio.

Thus, to produce `8.70mol` aluminium chloride, it will require `8.70mol` aluminium.

But this quantity of `Al` has a mass in grams of

`m=nxxM_r`

`=8.70molxx27g//mol`

`=234.9g`