How do you factor $y= x^2-6x+5$ ?

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Answer 1 · 2016-05-17T16:37:03

Factors are $y=(x-1)(x-5)$

If you have a quadratic function $ax^2+bx+c$ , to factorise it you should identify two numbers whose product is $ac$ and sum is $b$ .

Here in $y=x^2-6x+5$ , we should identify two numbers whose product is $5$ and sum is $-6$ .

Such numbers are $-5$ and $-1$ and now splitting middle term into these we get $y=x^2-5x-x+5$ or

$y=x(x-5)-1(x-5)=(x-1)(x-5)$ .

How do you factor y= x^2-6x+5y= x^2-6x+5 ?