How do you find the angle #alpha# such that #0<=alpha<=90# and #tanalpha=1.904#?

1 Answer
Jul 4, 2016

#alpha=62.2911^o=62^o17'28''#

Explanation:

It is given that #alpha# is in first quadrant as #0<=alpha<=90^o#.

As #tan60^o=sqrt3=1.732#, #alpha>60^o#.

However to find exact value, one needs to look at natural tangents table, which come along with logarithmic and trigonometric ratios.
Using them one can find that #alpha=62^o17'#.

Using calculators one gets more accurate value but in decimal terms and it gives #alpha=62.2911^o# and is equivalent to #62^o17'28''#