Question

Question #3e3f6

Answer 1

`~~204750.5L`

Explanation:

The volume of nitric acid splilled is 20000 gallons

We know 1 gallon =3.785 L (US)

So the volume of nitric acid
`=3.785xx20000=75700L`

Given its density =1.42g/cc
=1420g/L

So the mass of acid solution is
`75700xx1420g=107494000g`

The w/w percentage of this acid is 72%

So actual mass of acid in solution is`=(107494000xx72)/100g`
`=77395680g=(77395680g)/"63g/mol"=1228502.9 mol`
`"where molar mass of "HNO_3=63"g/mol"`

Now nutralisation reaction occurring
`HNO_3+NaHCO_3->NaNO_3+H_2O+CO_2`

This indicates that 1 mole acid is nutralised by 1 mole bicarbonate salt.So if 6M bicarbobate solution is used for nutralisation then volume of sodium bicarbonate solution required will be

`=(1228502.9mol)/"6mol/L"`

`~~204750.5L`