How do you factor #x^3-4x^2-36x+144# by grouping? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Shwetank Mauria Aug 7, 2016 #x^3-4x^2-36x+144 = (x+6)(x-6)(x-4)# Explanation: #x^3-4x^2-36x+144# = #x^2(x-4)-36(x-4)# = #(x^2-36)(x-4)# = #(x^2-6x+6x-36)(x-4)# = #(x(x-6)+6(x-6))(x-4)# = #(x+6) (x-6) (x-4)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 2180 views around the world You can reuse this answer Creative Commons License