Question

Question #db197

Answer 1

`ED=4`

Explanation:

Here ED will bisect `/_ADC=120^@`. So `/_ADE=1/2/_ADC=1/2xx120=60^@`

Again the diagonal of a rhombus bisrcts each perpendicularly.
So in `DeltaEAD->/_AED="Right angle"`

Now `(ED)/(AD)=cos/_ADE`

`:.ED=ADxxcos60^@=8xx1/2=4`