Question

How do you find the slope and intercept of `5(x-3y)=2(x+3)`?

Answer 1

Slope of the line is `1/5` and intercept on `y`-axis is `-2/5`

Explanation:

The equation of a line in slope intercept form is `y=mx+c`, where `y` is expressed in terms of `x` and then `m`, the coefficient of `x`, is slope and `c` the constant term is the value of intercept made by the line on `y`-axis.

In the equation `5(x-3y)=2(x+3)`, we simplify and write `y` in terms of `x`.

`5(x-3y)=2(x+3)`

`hArr5x-15y=2x+6` or

`-15y=2x-5x+6` or

`-15y=-3x+6` or

`y=(-3)/(-15)x+6/(-15)` or

`y=1/5 x-2/5`

Hence slope of the line is `1/5` and intercept on `y`-axis is `-2/5`.