Let #x = e^t + 3# and #y = e^(2t)+6e^t+9# how do you eliminate the parameter and write y in terms of x? Calculus Parametric Functions Introduction to Parametric Equations 1 Answer Ratnaker Mehta Sep 17, 2016 #y=x^2#. Explanation: Observe that, #y=e^(2t)+6e^t+9=(e^t+3)^2=x^2# Answer link Related questions How do you find the parametric equation of a parabola? How do you find the parametric equations for a line segment? How do you find the parametric equations for a line through a point? How do you find the parametric equations for the rectangular equation #x^2+y^2-25=0# ? How do you find the parametric equations of a circle? How do you find the parametric equations of a curve? What are parametric equations used for? What is the parametric equation of an ellipse? How do you sketch the curve with parametric equations #x = sin(t)#, #y=sin^2(t)# ? How do you find the vector parametrization of the line of intersection of two planes #2x - y - z... See all questions in Introduction to Parametric Equations Impact of this question 1761 views around the world You can reuse this answer Creative Commons License