Question

How do you write the trigonometric form into a complex number in standard form `9(cos58+isin58)`?

Answer 1

`9(cos58+isin58)=4.734+i7.632`

Explanation:

A complex number `r(costheta+isintheta)` can be written into complex form as `a+ib`,

where `a=rcostheta` and `b=rsintheta`

Hence `9(cos58+isin58)`

= `9cos58+i9sin58`

= `9xx0.526+i9xx0.848`

= `4.734+i7.632`