For #f(t)= (sint-cost,t)# what is the distance between #f(pi/4)# and #f(pi)#? Calculus Parametric Functions Introduction to Parametric Equations 1 Answer Douglas K. Oct 5, 2016 The distance is #~~2.56# Explanation: #f(pi/4) = (sin(pi/4) - cos(pi/4), pi/4) = (0, pi/4)# #f(pi) = (sin(pi) - cos(pi), pi) = (1, pi)# The distance is: #d = sqrt((1 - 0)² + (pi - pi/4)²# Answer link Related questions How do you find the parametric equation of a parabola? How do you find the parametric equations for a line segment? How do you find the parametric equations for a line through a point? How do you find the parametric equations for the rectangular equation #x^2+y^2-25=0# ? How do you find the parametric equations of a circle? How do you find the parametric equations of a curve? What are parametric equations used for? What is the parametric equation of an ellipse? How do you sketch the curve with parametric equations #x = sin(t)#, #y=sin^2(t)# ? How do you find the vector parametrization of the line of intersection of two planes #2x - y - z... See all questions in Introduction to Parametric Equations Impact of this question 1523 views around the world You can reuse this answer Creative Commons License