Question

What is the trigonometric form of `15 e^( ( pi)/12 i )`?

Answer 1

`15e^(pi/12i)=15(cos(pi/12)+isin(pi/12))`

Explanation:

Trigonometric form of `re^(itheta)=r(costheta+isintheta)`

Hence `15e^(pi/12i)=15(cos(pi/12)+isin(pi/12))`