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Answer 1 · 2016-10-08T19:06:57

#0.71"g"#

From the answer to the previous question, we know the moles of sulfuric acid = #0.705#.

#2"Al" + 3"H"_2"SO"_4 rarr "Al"_2("SO"_4)_3 + 3"H"_2#

Using this, we can work out the moles of hydrogen:

Reacting ratio of #"H"_2"SO"_4: "H"_2 = 3:3 = 1:1 therefore#

moles of #"H"_2 = 0.705#

#"n"="m"/"M"_"r" rarr 0.705 = "m"/1#

#"m"=0.705*1=0.705"g"#