How do solve #x^2<=9# and write the answer as a inequality and interval notation?

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Answer 1 · 2016-12-26T01:22:37

#x<=+-3 <=> x<=|3|#

#-3<=x<=3#

#x^2<=9#

Take the square root on both sides:

#sqrt(x^2)<=sqrt9#

#x<=+-3# which can also be written as #x<=|3|#

which is the same as

#-3<=x<=3#