Question

How do you integrate `int (root3x)`?

Answer 1

`int root(3)x dx = 3/4 xroot(3)x +C`

Explanation:

You can integrate using the power rule:

`int x^alpha dx = x^(alpha+1)/(alpha+1) + C`

In our case:

`int root(3)x dx = int x^(1/3)dx = x^(4/3)/(4/3) + C = 3/4 xroot(3)x +C`