Question

What is the vertex of the graph of `y = (x – 3)^2 + 4`?

Answer 1

Vertex is `(3,4)`

Explanation:

In a vertex form of equation such as

`(y-k)=a(x-h)^2`

the vertex is `(h,k)`

As `y=(x-3)^2+4`

`hArr(y-4)=1xx(x-3)^2`

the vertex is `(3,4)`
graph{(x-3)^2+4 [-7.585, 12.415, -0.96, 9.04]}