Question

What is the concentration in `"ppm"` when a `0.6068` mass of solute is dissolved in a `100*mL` of water?

Answer 1

We gots approx. `"6000 ppm"`

Explanation:

At these concentrations, the densities of the solution versus that of the pure solvent are tolerably close, so I am not going to consider the density.

We gots a concentration of `(0.6068*g)/(0.100*L)=6.068*g*L^-1`

`=6.068*g*10^3*mg*g^-1*L^-1`

`=6068*mg*L^-1`

`=6068*"ppm"`, because `"1 ppm"-=1*mg*L^-1`.