On a point #(ct,c/t)# on hyperbola #xy=c^2#, a normal is drawn which intersects the hyperbola at #(ct',c/(t'))#. Prove that #t^3t'=-1#?
1 Answer
Jul 28, 2017
Please see below.
Explanation:
The equation of hyperbola is
Let us find the equation of the normal.
Equation of hyprbola can be written as
hence slope of normal is given by
or
As this passes through
or
as
or