How do you write the equation #y-1=-2(x-5)# in slope intercept form?

1 Answer

Distribute the #-2# to the #x# and #-5#, add #1# to both sides of the equation.

Explanation:

Remember, slope-intercept form is represented as y=mx+b

Start on the right side of the equation, and distribute the #-2#.
#-2# times #x= -2x# and #-2(-5)=10#.

Now we have the equation #y-1= -2x+10#. The only thing left to do is add #1# to both sides of the equation so that the variable y is the only thing on the left side of the equation.

On the left hand side, the #-1# and #+1# will cancel each other out, leaving the variable #y#. On the right hand side, add #1# to the #10# only, to get #11#**.

#y=-2x+11#

We have obtained an equation in slope intercept form (y=mx+b), where #m=-2 and b=11#.