Question

How do you graph the equation `y=-3/7x+2`?

Answer 1

See a solution process below:

Explanation:

This equation is in slope intercept form. The slope-intercept form of a linear equation is: `y = color(red)(m)x + color(blue)(b)`

Where `color(red)(m)` is the slope and `color(blue)(b)` is the y-intercept value.

`y = color(red)(-3/7)x + color(blue)(2)`

Therefore:

The `y`-intercept is: `color(blue)(2)` or `(0, color(blue)(2))`

The slope is: `color(red)(m = -3/7)`

Slope is rise over run. So the line will go down `3` units while it goes to the right `7` units.

We can plot the `y`-intercept as:

graph{(x^2+(y-2)^2-0.025)=0}

We can plot the next point by going down `3` units and to the right `7` units which is at: `(7, -1)`

We can now draw a line through the two points to graph the line:

graph{(y + (3/7)x - 2)((x-7)^2+(y+1)^2-0.025)(x^2+(y-2)^2-0.025)=0}