How would you contrast single covalent bonds?

1 Answer
Oct 25, 2017

Well, let us contrast them on the basis of polarity.....

Explanation:

Polarity reflects charge separation of electron density between the bound atoms....

Homonuclear diatomic molecules, such as HH, and XX, dihydrogen, and the halogens are necessarily NON-POLAR because the bound atoms have the same electronegativity and thus electron density is shared equally...Bond polarity is also not a feature of the wealth of carbon chemistry, due to the small difference in electronegativity of carbon and hydrogen....and the capacity of carbon to catenate....to form long CC chains, along which substitution by heteroatoms can occur.

When two or more non-polar atoms are bound, say between HF or HOH, bond polarity manifests due to the difference in bond polarity, and this is the origin of intermolecular hydrogen bonding, i.e. on the back of dipole-dipole interactions.... +δHFδ, and +δH2Oδ. Of course this represents the extreme end of polar bond.....

THE bond in say H2S, BrCl would display much less charge separation, and much less polarity....because the bound atoms have a SMALLER difference in electronegativity.