Question

How do you find the vertex of a parabola `f(x) = -3x^2 + 6x -2`?

Answer 1

Vertex (1, 1)

Explanation:

`f(x) = - 3x^2 + 6x - 2`
x-coordinate of vertex:
`x = -b/(2a) = -6/-6 = 1`
y-coordinate of vertex:
`f(1) = - 3 + 6 - 2 = 1`
Vertex (1, 1)
graph{-3x^2 + 6x - 2 [-5, 5, -2.5, 2.5]}