How do you find the angles of a right triangle given A is 6" tall, B is 12" long, that leaves C as 13.4164?

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Answer 1 · 2018-05-16T07:06:29

#A=26.6^@#
#B=63.4^@#

Use sine rule

#[sin A]/a=[sin C]/c#

#[sin A]/6=[sin 90]/[6sqrt5]#

#sin A=6 xx 1/[6sqrt5]#

#sin A=1/[sqrt5]#

#A=sin^(-1)[1/[sqrt5]]#

#A=26.56505118#

#B= 90-A=> B=63.4349882#