Question

How do you graph using slope and intercept of `8x - 6y = -20`?

Answer 1

See below:

Explanation:

When an equation is in slope-intercept form

`y=mx+b`, we know that `m` is the slope and `b` is the `y`-intercept.

In our example, we only want a `y` on the left side, so we can start by subtracting `8x` from both sides to get

`-6y=-8x-20`

Divide all terms by `-6` to get

`y=4/3x+10/3`

We can start at our `y`-intercept, and from that point, go up `4` in the `y`-direction and right `3` in the `x`-direction. We get the graph

graph{y=4/3x+10/3 [-10, 10, -5, 5]}

Hope this helps!