Question #3e3f6

1 Answer
Jul 5, 2016

Answer:

#~~204750.5L#

Explanation:

The volume of nitric acid splilled is 20000 gallons

We know 1 gallon =3.785 L (US)

So the volume of nitric acid
#=3.785xx20000=75700L#

Given its density =1.42g/cc
=1420g/L

So the mass of acid solution is
#75700xx1420g=107494000g#

The w/w percentage of this acid is 72%

So actual mass of acid in solution is#=(107494000xx72)/100g#
#=77395680g=(77395680g)/"63g/mol"=1228502.9 mol#
#"where molar mass of "HNO_3=63"g/mol"#

Now nutralisation reaction occurring
#HNO_3+NaHCO_3->NaNO_3+H_2O+CO_2#

This indicates that 1 mole acid is nutralised by 1 mole bicarbonate salt.So if 6M bicarbobate solution is used for nutralisation then volume of sodium bicarbonate solution required will be

#=(1228502.9mol)/"6mol/L"#

#~~204750.5L#