# Question #a2839

Oct 8, 2016

#### Answer:

$0.71 \text{g}$

#### Explanation:

From the answer to the previous question, we know the moles of sulfuric acid = $0.705$.

$2 {\text{Al" + 3"H"_2"SO"_4 rarr "Al"_2("SO"_4)_3 + 3"H}}_{2}$

Using this, we can work out the moles of hydrogen:

Reacting ratio of ${\text{H"_2"SO"_4: "H}}_{2} = 3 : 3 = 1 : 1 \therefore$

moles of ${\text{H}}_{2} = 0.705$

$\frac{\text{n"="m"/"M"_"r" rarr 0.705 = "m}}{1}$

$\text{m"=0.705*1=0.705"g}$