1) No reaction; 2) no reaction; 3) formation of acetylide ion.
1) With hydroxide ion
Terminal alkynes are slightly acidic (
Thus, they can be deprotonated by a strong enough base.
Thus, water is a stronger acid than the alkyne, and hydroxide ion is a weaker base than acetylide ion.
The position of equilibrium is far to the left, so there is effectively no reaction.
b) With ammonia
Ammonia is a weaker base than hydroxide ion, so there will be no reaction with but-1-yne.
c) With amide ion
Ammonia is a weaker acid than a terminal alkyne, so its conjugate base is stronger than an acetylide ion.
The position of equilibrium will be to the right, forming an acetylide ion.