Question #109b4

Jan 26, 2017

Step-1 $C {H}_{3} C {H}_{2} C O O H \stackrel{N {H}_{3}}{\to} C {H}_{3} C {H}_{2} C O O N {H}_{4}$

Step-2
$C {H}_{3} C {H}_{2} C O O N {H}_{4} \stackrel{\Delta}{\to} C {H}_{3} C {H}_{2} C O N {H}_{2}$

Step-3
$C {H}_{3} C {H}_{2} C O N {H}_{2} \stackrel{B {r}_{2} \text{/} N a O H \left(a q\right)}{\to} C {H}_{3} C {H}_{2} N {H}_{2}$

Step-4
$C {H}_{3} C {H}_{2} N {H}_{2} \stackrel{N a N {O}_{2} \text{/dil} H C l}{\to} C {H}_{3} C {H}_{2} O H$

This conversion can be brought about by using Hoffman degradation reaction (step-3) following the steps as shown above.