Question

Question #fa7ed

Answer 1

`[1-sqrt2]/3 and [1+sqrt2]/3`

Explanation:

`9x^2-6x+1 = 2`
or, `9x^2-6x+1-2=0`
or, `(3x)^2-2.3x.1+(1)^2- [sqrt2]^2=0`
or,`(3x-1)^2-[sqrt2]^2=0`
or, `[3x-1+sqrt2][3x-1-sqrt2]=0`
or, `[3x-1+sqrt2] = 0, [3x-1-sqrt2]=0`
or, `3x= 1-sqrt2, 3x= 1+sqrt2`
or, `x = [1-sqrt2]/3 and [1+sqrt2]/3`