# How do you solve for x in the equation (x-3)^2+25=0?

Mar 16, 2018

Move $25$ to the other side:

${\left(x - 3\right)}^{2} = 25$

Take the square root of both sides to get rid of the square:

$\sqrt{{\left(x - 3\right)}^{2}} = \sqrt{- 25}$

$x - 3 = \pm 5 i$

$x = 3 \pm 5 i$