Question

How do you solve for x in the equation `(x-3)^2+25=0`?

Answer 1

Move `25` to the other side:

`(x-3)^2=25`

Take the square root of both sides to get rid of the square:

`sqrt((x-3)^2)=sqrt(-25)`

`x-3=+-5i`

`x=3+-5i`