# How do you solve 4x^2-49=0 by taking square roots?

Apr 16, 2018

$x = \pm \frac{7}{2}$

#### Explanation:

$4 {x}^{2} - 49 = 0$

1. Add $49$ to both sides
$4 {x}^{2} = 49$

2. Divide both sides by $4$
${x}^{2} = \frac{49}{4}$

3. Square root both sides
$x = \pm \sqrt{\frac{49}{4}}$
$x = \pm \frac{7}{2}$