# How do you use square roots to solve 2(x+3)^2=8?

Apr 15, 2018

$x = - 1 , - 5$

#### Explanation:

Our first step would be to divide both sides by $2$. We get:

${\left(x + 3\right)}^{2} = 4$

We can take the $\pm$ square root of both sides, and we will now have two equations:

The first:
$x + 3 = 2$

$\textcolor{b l u e}{\implies x = - 1}$

The second:
$x + 3 = - 2$

$\textcolor{b l u e}{\implies x = - 5}$

We have two equations because we need to take the $\pm$ square root of both sides, because when you take the sqrt of a number, there will always be a positive and a negative answer.

Hope this helps!

Apr 15, 2018

Express the answer with surds, it's not possible here as the surd is a perfect square.

#### Explanation:

So

$2 {\left(x + 3\right)}^{2} = 8$

${\left(x + 3\right)}^{2} = 4$

$\left(x + 3\right) = \pm \sqrt{4}$
$x = \pm 2 - 3$