How do you solve #4x^2=52# solve using the square root property?

1 Answer
Feb 8, 2015

Using the square root property to solve this problem involves the following steps.

Isolate the squared term. (Already isolated.)

#4x^2 = 52#

Take the square of both sides, indicating that the solution can be positive or negative.

#sqrt(4x^2) = +-sqrt(52)#

Solve for x.

#2x = +-sqrt(4·13)#

#2x = +-sqrt(4)·sqrt(13)#

#2x = +-2 sqrt(13)#

#x = +-sqrt(13)#