# Question #fbce3

Sep 20, 2017

Four

#### Explanation:

2,2-dimethylpentane looks like this:

The $C l$ may be at one of the three methyl groups at the end (the C1 also forms a methyl group). If it is on one of the 2,2-methyls, we change that to C1:

1-chloro 2,2-dimethylpentane

Or it may be at C3, C4 or C5

3-chloro 2,2-dimethylpentane

4-chloro 2,2-dimethylpentane

5-chloro 2,2-dimethylpentane

The C2 cannot take the $C l$ as it already has its four bonds occupied bij other carbon atoms (there is no H to replace).