How does "sodium oleate" react with HCl?

Here, $\text{sodium oleate}$ is the conjugate base of a weak acid, and so:
C_17H_33CO_2^(-)""^(+)Na(aq) + HCl(aq) rarr C_17H_33CO_2H(aq) + NaCl(aq)
The product acid, $\text{oleic acid}$, is the principal component of olive oil: it probably has next to no solubility in water.