# On a point #(ct,c/t)# on hyperbola #xy=c^2#, a normal is drawn which intersects the hyperbola at #(ct',c/(t'))#. Prove that #t^3t'=-1#?

##### 1 Answer

Jul 28, 2017

Please see below.

#### Explanation:

The equation of hyperbola is

Let us find the equation of the normal.

Equation of hyprbola can be written as

hence slope of normal is given by

or

As this passes through

or

as

or