Question #52abf
1 Answer
Mar 10, 2017
Yes, you are correct. The curve does indeed have x-intercepts at
Explanation:
A point that lies on the x-axis will be of the form
To find the value of
#0^3(e^x) - x^2 + 5e^0 = 1#
#-x^2 + 5(1) = 1#
#-x^2 + 4= 0#
#4 = x^2#
#x = +-2#
Hopefully this helps!