# Question #52abf

##### 1 Answer

Mar 10, 2017

Yes, you are correct. The curve does indeed have x-intercepts at

#### Explanation:

A point that lies on the x-axis will be of the form

To find the value of

#0^3(e^x) - x^2 + 5e^0 = 1#

#-x^2 + 5(1) = 1#

#-x^2 + 4= 0#

#4 = x^2#

#x = +-2#

Hopefully this helps!