How is #C_6H_11Br# made?

1 Answer
anor277
Apr 8, 2017

You might want to qualify this question. At the moment, I don't know what you ask.

Explanation:

Cyclohexane, #C_6H_12#, has one, so-called, #"degree of unsaturation"#. We refer to the saturated alkane, i.e. #C_nH_(2n+2)#. The ring junction in cyclohexanol reduces the hydrogen count by 2.

As to how to make #"cyclohexyl bromide"# from #"cyclohexane"#; the standard means is to halogenate the cycloalkane with #"NBS"# under UV light:

#C_6H_12 + Br_2 stackrel(hnu)rarr C_6H_11Br + HBr#

Hydrolysis of the cyclohexyl bromide would yield the alcohol.

Anyway, it's over to you..........

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