# How is C_6H_11Br made?

Apr 8, 2017

You might want to qualify this question. At the moment, I don't know what you ask.

#### Explanation:

Cyclohexane, ${C}_{6} {H}_{12}$, has one, so-called, $\text{degree of unsaturation}$. We refer to the saturated alkane, i.e. ${C}_{n} {H}_{2 n + 2}$. The ring junction in cyclohexanol reduces the hydrogen count by 2.

As to how to make $\text{cyclohexyl bromide}$ from $\text{cyclohexane}$; the standard means is to halogenate the cycloalkane with $\text{NBS}$ under UV light:

${C}_{6} {H}_{12} + B {r}_{2} \stackrel{h \nu}{\rightarrow} {C}_{6} {H}_{11} B r + H B r$

Hydrolysis of the cyclohexyl bromide would yield the alcohol.

Anyway, it's over to you..........