Question

For `f(t)= (t^2,t^3)` what is the distance between `f(1)` and `f(3)`?

Answer 1

`~~ 27.2` units

Explanation:

`f(1) = (1,1)`
`f(3)=(9,27)`

By Pythagoras, the distance, `d`, between these points is:

`d^2 = (27-1)^2 + (9-1)^2`
`:. d^2 = 26^2 + 8^2`
`:. d^2 = 676 + 64`
`:. d^2 = 740`
`:. d = sqrt(740) ~~ 27.2`