How do I find #lim_((x,y) to (5,4)) e^sqrt (3x^2+2y^2)#, if it exists? Calculus Limits Determining Limits Graphically 1 Answer Massimiliano Mar 22, 2015 The answer is: #e^sqrt107#. In fact: #lim_((x,y) to (5,4)) e^sqrt (3x^2+2y^2)=e^(sqrt(3*25+2*16))=e^sqrt107#. Answer link Related questions How do you find #lim_(x->5)(x^2+2)# using a graph? How do i graph limits? How do you find limits on a graphing calculator? How do you use a graph to determine limits? What is the limit as x approaches infinity of a constant? What is the limit as x approaches infinity of #6cos(x)#? What is the limit as x approaches infinity of #1.001^x#? What is the limit as x approaches 0 of #x/arctan(4x)#? What is the limit as x approaches 0 of #cotx/lnx#? What is the limit as x approaches 0 of #(1+2x)^cscx#? See all questions in Determining Limits Graphically Impact of this question 3942 views around the world You can reuse this answer Creative Commons License