# How do solve x^2<=9 and write the answer as a inequality and interval notation?

$x \le \pm 3 \iff x \le | 3 |$

$- 3 \le x \le 3$

#### Explanation:

${x}^{2} \le 9$

Take the square root on both sides:

$\sqrt{{x}^{2}} \le \sqrt{9}$

$x \le \pm 3$ which can also be written as $x \le | 3 |$

which is the same as

$- 3 \le x \le 3$