# How do use the method of translation of axes to sketch the curve #x^2+y^2+2x-6y+6=0#?

##### 1 Answer

Jan 24, 2017

#### Answer:

See the method below

#### Explanation:

We rewrite the equation by completing the squares

This is a circle, center

We define new axes

and

This is a circle, center

graph{((x+1)^2+(y-3)^2-4)(x^2+y^2-4)=0 [-10, 10, -5, 5]}