# Where is the center of the graph of (x+3)^2+(y-2)^2=4?

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$
where $\left(h , k\right)$ is the center of the circle and $r$ is the radius of the circle
The center of the circle is $\left(- 3 , 2\right)$. You need to use the opposite signs for the numbers used in place of $\left(h , k\right)$