# How do use the method of translation of axes to sketch the curve #x^2+y^2-4x+3=0#?

##### 1 Answer

Jan 6, 2018

We have a conic:

# x^2+y^2-4x+3 = 0 #

We rearrange and complete the square of the

# (x^2-4x) +(y^2) + 3 = 0 #

# :. (x-2)^2-(2)^2 + y^2 + 3 = 0 #

# :. (x-2)^2-4 + y^2 + 3 = 0 #

# :. (x-2)^2 + y^2 = 1 #

Comparing with:

# (x-a)^2+(y-b)^2 = r^2 #

We see that the conic is a circle of radius

Alternatively, if we compare to the origin centred circle

So the graph is as follows:

graph{x^2+y^2-4x+3 = 0 [-3.656, 6.344, -2.5, 2.5]}