# If the equation of a conic section is #(x+6)^2/81-(y+1)^2/16=1#, how has its center been translated?

##### 1 Answer

Feb 2, 2015

This is the equation of an hyperbola centered in the point

The equation of an hyperbola centered in

If the second member is

E.G.:

graph{x^2/4-y^2/9=1 [-10, 10, -5, 5]}

If the second member is

E.G.:

graph{x^2/4-y^2/9=-1 [-10, 10, -5, 5]}

The equation of an hyperbola centered in

So, our hyperbola is:

graph{(x+6)^2/81-(y+1)^2/16=1 [-20, 10, -20, 20]}