# How do you convert #x^2+(y-4)^2=16# to polar form?

##### 2 Answers

May 3, 2016

#### Explanation:

If

Hence,

May 3, 2016

#### Explanation:

To convert from Cartesian to Polar coordinates use the following formulae that link them.

#• x=rcostheta" and " y=rsintheta#

#x^2+y^2-8y+16=16 " (expanding bracket) "#

#rArrr^2cos^2theta+r^2sin^2theta-8rsintheta+16-16=0# then

#r^2(cos^2theta+sin^2theta)-8rsintheta=0# using the identity:

#cos^2theta+sin^2theta=1 #

#rArr r^2=8rsintheta" and dividing both sides by r "#

#rArr r=8sintheta#